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This video provides a quick comparison of the reactivity of alkenes and benzene with halogens. It focuses on the differences in their electron density and how that impacts their reaction mechanisms.
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Okay, assuming this is for practice related to the reactivity of alkenes and benzene (as described in the transcript), here are some practice questions:
1. Mechanism Identification:
Question: Identify the type of reaction (electrophilic addition or electrophilic substitution) that occurs when each of the following reacts with bromine (Br₂):
Answer: Ethene undergoes electrophilic addition; Benzene undergoes electrophilic substitution.
2. Reagent Identification:
Question: What additional reagent is typically required for benzene to react with Br₂? Why is this reagent necessary?
Answer: A halogen carrier catalyst (like FeBr₃ or AlBr₃) is necessary. It is needed to generate an electrophile strong enough to react with the delocalized electrons of benzene.
3. Product Prediction:
Question: Predict the major product formed when propene (CH₃CH=CH₂) reacts with Br₂. Draw the structure.
Answer: 1,2-Dibromopropane (CH₃CHBrCH₂Br). (You would draw the structural formula here.)
4. Electron Density Explanation:
Question: Explain why the electron density in the pi bond of an alkene is higher than the electron density in the pi electrons of benzene.
Answer: In alkenes, the pi electrons are localized between two carbon atoms. In benzene, the pi electrons are delocalized across all six carbon atoms in the ring, resulting in a lower electron density at any one point.
5. Short Answer: Compare and contrast the reactivity of alkenes and benzene with bromine. Explain the differences in their mechanisms and why these differences arise.
These questions require understanding of the concepts discussed in the provided transcript. Remember to draw out chemical structures where appropriate. You can adapt the complexity and type of questions based on your specific learning needs.